## Basic College Mathematics (9th Edition)

Area of the triangle = $A$ = 1914 m$^{2}$ Perimeter of the triangle = $P$ = 202 m
Area of a Triangle: $A$ = $\frac{1}{2}$$b$$h$ Therefore: $A$ =$\frac{1}{2}$(58 m)(66 m) $A$ = 1914 m$^{2}$ Perimeter of a Triangle: $P$ = $a$ + $b$ + $c$ Therefore: $P$ = 72 m + 72 m + 58 m $P$ = 202 m