Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.5 Triangles - 8.5 Exercises - Page 566: 7

Answer

The area of the triangle is $30.75$ yd$^{2}$ and the perimeter is $26.25$ yd.

Work Step by Step

1. Find the area of the triangle Let $A =$ area of the triangle $A = base \times height \div 2$ $A = (10.25 \times 6) \div 2$ $A = 30.75$ yd$^{2}$ 2. Find the perimeter of the triangle Let $P =$ perimeter of the triangle $P = a + b + c$ $P = 9 + 7 + 10.25$ $P = 26.25$ yd
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