Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises: 25

Answer

Difference in playing area = 4600 yd$^{2}$

Work Step by Step

First, find the area of the largest field. Area of a rectangle: $A$ = $l$$w$ A$_{large}$ = (80 yd)(120 yd) A$_{large}$ = 9600 yd$^{2}$ Second, find the area of the smallest field. Area of a rectangle: $A$ = $l$$w$ A$_{small}$ = (50 yd)(100 yd) A$_{small}$ = 5000 yd$^{2}$ Finally, to find the difference in playing room subtract the area of the smallest field from the area of the largest field. Difference in area = $D$ $D$ = A$_{large}$ - A$_{small}$ $D$ = 9600 yd$^{2}$ - 5000 yd$^{2}$ $D$ = 4600 yd$^{2}$
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