# Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises: 27

Width of the field = 53 yd

#### Work Step by Step

Area of a rectangle: $A$ = $l$$w A = 5300 yd^{2} 5300 yd^{2} = l$$w$ 5300 yd$^{2}$ = (100 yd) * $l$ $l$ = 5300 yd$^{2}$ / 100 yd $l$ = 53 yd

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