Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises: 26

Answer

a) $A$$_{coleman}$ = 169 ft$^{2}$ $P$$_{coleman}$ = 52 ft $F$$_{coleman}$ $\approx$ 21 ft$^{2}$ b) $A$$_{bauer}$ = 144 ft$^{2}$ $P$$_{bauer}$ = 48 ft $F$$_{bauer}$ = 24 ft$^{2}$

Work Step by Step

a) Area of a square: $A$ = $s$$^{2}$ $A$$_{coleman}$ = (13 ft)$^{2}$ $A$$_{coleman}$ = 169 ft$^{2}$ Perimeter of a square: $P$ = 4$s$ $P$$_{coleman}$ = 4(13 ft) $P$$_{coleman}$ = 52 ft To find the number of square feet per camper we simply divide the area of the tent by the number of campers. Therefore: Floor Space = $F$ $F$$_{coleman}$ = 169 ft$^{2}$ / 8 $F$$_{coleman}$ = 21.13 ft$^{2}$ or $F$$_{coleman}$ $\approx$ 21 ft$^{2}$ b) Area of a square: $A$ = $s$$^{2}$ $A$$_{bauer}$ = (12 ft)$^{2}$ $A$$_{bauer}$ = 144 ft$^{2}$ Perimeter of a square: $P$ = 4$s$ $P$$_{bauer}$ = 4(12 ft) $P$$_{bauer}$ = 48 ft To find the number of square feet per camper we simply divide the area of the tent by the number of campers. Therefore: Floor Space = $F$ $F$$_{bauer}$ = 144 ft$^{2}$ / 6 $F$$_{bauer}$ = 24 ft$^{2}$
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