## Basic College Mathematics (9th Edition)

$A$ = 100 ft$^{2}$ $P$ = 40 ft
Since the length and width of this object are same it is a square. Area of a square: $A$=$s$$^{2}$ $A$ = (10 ft)$^{2}$ $A$ = 100 ft$^{2}$ Perimeter of a square: $P$ = 4$s$ $P$ = 4 * 10 ft $P$ = 40 ft