## Basic College Mathematics (9th Edition)

$P$ = 50 in $A$ = 126 in$^{2}$
Perimeter = $P$ $P$ = 2$l$ + 2$w$ $P$ = 2(18 in) + 2(7 in) $P$ = 36 in + 14 in $P$ = 50 in Area = $A$ $A$ = $l$$w$ $A$ = 18 in * 7 in $A$ = 126 in$^{2}$