Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises: 4

Answer

$P$ = 50 in $A$ = 126 in$^{2}$

Work Step by Step

Perimeter = $P$ $P$ = 2$l$ + 2$w$ $P$ = 2(18 in) + 2(7 in) $P$ = 36 in + 14 in $P$ = 50 in Area = $A$ $A$ = $l$$w$ $A$ = 18 in * 7 in $A$ = 126 in$^{2}$
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