Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises: 8

Answer

$A$ = 136 cm$^{2}$ $P$ = 50 cm

Work Step by Step

Since the length and width of the object are different it is a rectangle. Area of a rectangle: $A$ = $l$ * $w$ $A$ = 8 cm * 17 cm $A$ = 136 cm$^{2}$ Perimeter of a rectangle: $P$ = 2$l$ + 2$w$ $P$ = 2(8 cm) + 2(17 cm) $P$ = 16 cm + 34 cm $P$ = 50 cm
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