Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 16 - Vector Calculus - 16.8 Exercises - Page 1151: 1

Answer

$\iint_{H} curl F \cdot dS=\iint_{P} curl F \cdot dS=\iint_{C} F \cdot dr$ and $C$ is the circle $x^2+y^2=4$ oriented counter-clockwise.

Work Step by Step

Stokes' Theorem states that $\iint_{S} curl F \cdot dS=\iint_{C} F \cdot dr$ and $C$ is the boundary of the surface oriented counter-clockwise. Both surfaces $H$ and $P$ have same boundary of the circle $x^2+y^2=4$ Thus, Stokes' Theorem can be written as: $\iint_{H} curl F \cdot dS=\iint_{P} curl F \cdot dS=\iint_{C} F \cdot dr$ and $C$ is the circle $x^2+y^2=4$ oriented counter-clockwise.
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