Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 16 - Vector Calculus - 16.8 Exercises - Page 1151: 17

Answer

$3$

Work Step by Step

Stokes' Theorem states that $\iint_{S} curl F \cdot dS=\int_{C} F \cdot dr $ The work done by a force $F$ in moving a particle along path $C$ is: $ \iint_{C} F \cdot dr $ Suppose $S$ to be the part inside the rectangle formed by four points. We have: $curl F=8 yi+2 z j+2y k$ Now, $\iint_{S} curl F \cdot dS=\iint_{D} 2y-z dA=\dfrac{3}{2} \iint_{D}y dA$ or, $=\dfrac{3}{2} \int_{0}^1 \int_0^2 y dy dx$ or, $=\dfrac{3}{2} \int_{0}^{1} [\dfrac{y^2}{2}]_0^2 dx$ or, $=\dfrac{3}{2} \int_0^1 2 dx$ Now, work done =$\int_{C} F \cdot dr =3$
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