Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 16 - Vector Calculus - 16.2 Exercises - Page 1098: 46

Answer

$16, 245 ft-lbs $

Work Step by Step

The magnitude of the gravitational force acting on the man plus the can of paint is equal to $=(160+m)lbs$ Since, we are moving in the upward direction $F \cdot dr=(185-\dfrac{9r}{s}) dr$ Work done, $W=\int_C F\cdot dr= \int_0^s (185-\dfrac{9r}{s}) dr$ Since $C$ shows a vertical line segment connecting the bottom and top of the silo, thus we have Work done, $W=\int_C F\cdot dr=[185r-\dfrac{9r^2}{2s}]_0^s=185 s-4.5 s =16, 245 ft-lbs $
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