Answer
$4.65 Hz/s$ and $576.6$ Hz
Work Step by Step
The perceived frequency is given by: $=[\dfrac{332+34}{332-40}] (460)=576.6$ Hz
Take the derivative:
$\dfrac{d}{dt}[\dfrac{C+V_0}{C-f_s}f] =[\dfrac{(C-f_s)(C+V_0)'-(C+V_0)(C-V_s)}{(C-f_s)^2}]f$
Re-write as:
$\dfrac{d}{dt}[\dfrac{C+V_0}{C-f_s}f] =\dfrac{(C-f_s)(V_0)'+(C+V_0)(V_s)}{(C-f_s)^2}f$
After plugging in the given values, we get:
$\dfrac{d}{dt}[\dfrac{C+V_0}{C-f_s}f]=\dfrac{(332-40) \times (1.2)+(332+34) \times (1.4)}{(332-40)^2} \times 460=4.65 Hz/s$
