Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 14 - Partial Derivatives - 14.3 Exercises - Page 936: 5

Answer

(a) Positive (b) Negative

Work Step by Step

(a) Since the graph of $f$ increases for $z$, if we start at $(1, 2)$ and move in positive x- direction, this represents the positive values of $f$. Thus,$f_{x} (1,2)$ is positive. (b) Since the graph of $f$ decreases, if we start at $(1, 2)$ and move in the positive y- direction, this represents the negative values of $f$. Thus,$f_{y} (1,2)$ is negative.
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