Answer
$$\frac{dz}{dx} = 20 (2x + 3y)^9$$ $$\frac{dz}{dy} = 30(2x + 3y)^9$$
Work Step by Step
$$z = (2x + 3y)^{10}$$ $$u = 2x + 3y, u' = 2$$ $$\frac{dz}{dx} = u^{10}(u')$$ $$\frac{dz}{dx} = 10u^9(2) = 20u^9$$ $$\frac{dz}{dx} = 20 (2x + 3y)^9$$
$$u = 2x + 3y, u' = 3$$ $$\frac{dz}{dy} = u^{10}(u')$$ $$\frac{dz}{dy} = 10u^9(3) = 30u^9$$ $$\frac{dz}{dy} = 30(2x + 3y)^9$$
