Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.3 Exercises - Page 830: 9

Answer

$-15$

Work Step by Step

The dot product of two vectors $\mathbf a$ and $\mathbf b$ is $|\mathbf a||\mathbf b|\cos \theta $, where $\theta $ is the angle between the two vectors. So if $|\mathbf a|=6$, $|\mathbf b|=5$, and the angle between $\mathbf a$ and $\mathbf b$ is $\frac{2\pi}{3}$, then $$\mathbf a \cdot \mathbf b=|\mathbf a||\mathbf b|\cos (\frac{2\pi}{3})=6(5)(-\frac{1}{2})=-3(5)=-15.$$
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