Answer
$14$
Work Step by Step
The dot product of two vectors $\mathbf a= \langle a_1,a_2 \rangle$ and $\mathbf b= \langle b_1,b_2 \rangle$ is $a_1b_1+a_2b_2$.
So for $\mathbf a= \langle -2,\frac{1}{3} \rangle$ and $\mathbf b= \langle -5,12 \rangle$, $$\mathbf a \cdot \mathbf b =(-2)(-5)+\frac{1}{3}(12)=10+4=14.$$
