Answer
$P=0.339(1.169)^{t}$
where $t$ is the number of years after 1994.
.
Work Step by Step
Using desmos.com, we enter the table with variables $t$ and $P$.
We enter in a free cell
$P\sim Ab^{t}$
place tick in "log mode" to obtain an exponential regression formula tying $P$ to $t$, and the calculator returns (see image):
$A=0.339, b=1.169$
with the correlation coefficient $r$ being close to $1$, indicating a good fit.
The model is
$P=0.339(1.169)^{t}$
where $t$ is the number of years after 1994.
