Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 645: 88

Answer

${{\$}} 42,395.90$

Work Step by Step

Contiuous compounding is modeled by $A=Pe^{rt}$. Here, $P=2000, r=0.31, t=10$ $A=2000e^{0.31(10)}\approx 44395.90256$ The interest earned is the difference $44,395.90-2000={{\$}} 42,395.90$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.