Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 645: 89

Answer

$S(t)=4.9e^{0.032t}$ million homes in 2010, $\quad 5.2$ million homes in 2012, $\quad 5.6$ million homes

Work Step by Step

Continuous growth model:$\quad f(x)=Ae^{rx}$ We use the notation: $\quad S(t)=S_{0}e^{kt}$ where $S_{0}=4.9,k=0.032, t=$ years after 2008. Thus, our model is $S(t)=4.9e^{0.032t}$ million homes For the year 2010, $t=2$ $S(2)=4.9e^{0.032(2)}\approx 5.22385$ For the year 2012, $t=4$ $S(4)=4.9e^{0.032(4)}\approx 5.56910$
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