Answer
$C=-800p+3,320,000$
Work Step by Step
As a function of q, cost is
$C=120,000+80,000q$
To express C as a function of p, substitute $q=-0.01p+40$
$C=120,000+80,000(-0.01p+40)$
$C=120,000-800p+3,200,000$.
$C=-800p+3,320,000$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 9 - Section 9.1 - Quadratic Functions and Models - Exercises - Page 630: 36c
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