Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.1 - Quadratic Functions and Models - Exercises - Page 630: 37

Answer

$f(t)=-6.25t^{2}-100t+1200$ In 2008, the model predicts ${{\$}} 1425$ billion, ${{\$}} 25$ billion lower than the actual value.

Work Step by Step

$ y_{1}\sim ax_{1}^{2}+bx+c$ Result: $f(t)=-6.25t^{2}-100t+1200$ The year 2008 is 18 years after 1990, $f(18)=1425$ billion, The chart in exercise 19 has this value to be ${{\$}} 1450$ billion, so the model predicts ${{\$}} 25$ billion lower than the actual value.
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