Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.1 - Quadratic Functions and Models - Exercises - Page 630: 34

Answer

$C=-200x+3400.$ $P=-40x^{2}+800x-3400$ At ${{\$}} 10\quad $per T-shirt, the maximum profit is ${{\$}} 600$ per week.

Work Step by Step

As a function of $q$, monthly cost is $C=5q+400$. To express C as a function of x, substitute $q=-40x+600$: $C=5(-40x+600)+400$ $C=-200x+3400$. The profit is$ \quad P=R-C$ $P=xq-C$ $P=-40x^{2}+800x-3400$ The graph of P is a parabola that opens down. The profit is largest at the vertex, when $x=-b/(2a)$ $x=-\displaystyle \frac{800}{-2\times 40}= {{\$}} 10\quad $ per T-shirt. The corresponding profit is $P=-40(10)^{2}+800(10)-3400$ $P={{\$}} 600$ per week.
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