Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 8 - Review - Review Exercises - Page 607: 7

Answer

$2,2,2.739$

Work Step by Step

We are given that $x=-1,0,2,3,6$ Now, we will find. $\bf{Mean}$$=\dfrac{-1+2+0+3+6}{5}=2$ $\bf{Median}$$=[\dfrac{(5+1)}{2}]^{th}=\text{3rd term}=2$ Therefore, $\bf{Standard \space Deviation}$$=\dfrac{(-1-2)^2+(2-2)^2+(0-2)^2+(3-2)^2+(6-2)^2}{5-1} \\=\dfrac{9+0+4+1+16}{4}\\=\dfrac{30}{4}\\=2.739$
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