Answer
$5,5,1$
Work Step by Step
We are given that $x=4,4,5,6,6$ (ascending order)
Now, we will find.
$\bf{Mean}$$=\dfrac{4+4+5+6+6}{5}=5$
$\bf{Median}$$=[\dfrac{(5+1)}{2}]^{th}=\text{3rd term}=5$
Therefore, $\bf{Standard \space Deviation}$$=\dfrac{(5-4)^2+(5-4)^2+(5-5)^2+(5-6)^2+(5-6)^2}{5-1} \\=\dfrac{1+1+0+1+1}{4}\\=1$
