Answer
$0$ and $1$
Work Step by Step
Consider an example: $x=-1,-1,-1,1,1,1$
Now, we will find.
$\bf{Mean}$$=\dfrac{-1-1-1+1+1+1}{6}=0$
Therefore, $\bf{Standard \space Deviation}$$=\dfrac{(0+1)^2+(0+1)^2+(0+1)^2+(0-1)^2+(0-1)^2+(0-1)^2}{6} \\=1$
