Answer
$\left[\begin{array}{rr}
-1 & -1\\
1 & -1\\
-1 & 5
\end{array}\right]$
Work Step by Step
$A=\left[\begin{array}{ll}
0 & -1\\
1 & 0\\
-1 & 2
\end{array}\right], \quad B=\left[\begin{array}{ll}
0.25 & -1\\
0 & 0.5\\
-1 & 3
\end{array}\right],\quad C=\left[\begin{array}{ll}
1 & -1\\
1 & 1\\
-1 & -1
\end{array}\right]$.
$(2A-C)_{ij}=2a_{ij}-c_{ij}$
---
$2A-C$=$\left[\begin{array}{ll}
2(0)-1 & 2(-1)-(-1)\\
2(1)-1 & 2(0)-1\\
2(-1)-(-1) & 2(2)-(-1)
\end{array}\right]$=$\left[\begin{array}{ll}
-1 & -1\\
1 & -1\\
-1 & 5
\end{array}\right]$