Answer
$\left[\begin{array}{rr}
-1 & 0\\
0 & -1\\
0 & 3
\end{array}\right]$
Work Step by Step
$A=\left[\begin{array}{ll}
0 & -1\\
\mathrm{l} & 0\\
-1 & 2
\end{array}\right], \quad B=\left[\begin{array}{ll}
0.25 & -1\\
0 & 0.5\\
-1 & 3
\end{array}\right],\quad C=\left[\begin{array}{ll}
1 & -1\\
1 & 1\\
-1 & -1
\end{array}\right]$.
$(A-C)_{ij}=A_{ij}+C_{ij}$
$A-C=\left[\begin{array}{ll}
0-1 & -1-(-1)\\
1-1 & 0-1\\
-1-(-1) & 2-(-1)
\end{array}\right]=\left[\begin{array}{rr}
-1 & 0\\
0 & -1\\
0 & 3
\end{array}\right]$