Answer
$\left[\begin{array}{rr}
0.5 & -2.5\\
2.5 & 0.5\\
-2.5 & 3.5
\end{array}\right]$
Work Step by Step
$A=\left[\begin{array}{ll}
0 & -1\\
1 & 0\\
-1 & 2
\end{array}\right], \quad B=\left[\begin{array}{ll}
0.25 & -1\\
0 & 0.5\\
-1 & 3
\end{array}\right],\quad C=\left[\begin{array}{ll}
1 & -1\\
1 & 1\\
-1 & -1
\end{array}\right]$.
$(2A+0.5C)_{ij}=2a_{ij}+0.5c_{ij}$
---
$2A-C$=$\left[\begin{array}{ll}
2(0)+0.5(1) & 2(-1)+0.5(-1)\\
2(1)+0.5(1) & 2(0)+0.5(1)\\
2(-1)+0.5(-1) & 2(2)+0.5(-1)
\end{array}\right]=\left[\begin{array}{ll}
0.5 & -2.5\\
2.5 & 0.5\\
-2.5 & 3.5
\end{array}\right]$