Answer
The number of visits that day was about 140,000.
Work Step by Step
1.Let's try to substitute the number of crashes and solve for "x" in the first function:
$c(x) = 0.03x + 2$
$8 = 0.03x + 2$
$8 - 2 = 0.03x$
$6 = 0.03x$
$\frac{6}{0.03} = \frac{0.03x}{0.03}$
$200 = x$
- But, that equation is only valid if $0 \leq x \leq 50$, and 200 is greater than 50. Therefore, we will have to use the second equation:
$c(x) = 0.05x + 1$
$8= 0.05x + 1$
$8 - 1 =0.05x$
$7 = 0.05x$
$\frac{7}{0.05} = \frac{0.05x}{0.05}$
$140 = x$
$140$ is greater than 50, so, that value is valid,
- Therefore, the number of visits that day was about 140,000.
