Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 1 - Review - Review Exercises - Page 107: 29a

Answer

When there are 10,000 visits, the website will crash, on average, 2.3 times, when there are 50,000 visits, the website will crash, on average, 3.5 times, and when there are 100,000 visits, the website will crash , on average, 6 times.

Work Step by Step

1. When there are 10,000 visits: $x = \frac{visits}{1,000} = \frac{10,000}{1,000} = 10$ "$0 \leq 10 \leq 50$", so, we should use the first function : $c(x) = 0.03x +2$ - Substitute the "x" value in that function: $c(x) = 0.03(10) + 2 = 0.3 + 2 = 2.3$ 2. When there are 50,000 visits: $x = \frac{visits}{1,000} = \frac{50,000}{1,000} = 50$ "$0 \leq 50 \leq 50$", so, we should use the first function : $c(x) = 0.03x +2$ - Substitute the "x" value in that function: $c(x) = 0.03(50) + 2 = 1.5 + 2 = 3.5$ 3. When there are 100,000 visits: $x = \frac{visits}{1,000} = \frac{100,000}{1,000} = 100$ "$100 \gt 50$", so, we should use the second function : $c(x) = 0.05x +1$ - Substitute the "x" value in that function: $c(x) = 0.05(100) + 1 = 5 + 1 = 6$
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