Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises: 8

Answer

$6x^{2} -14x+8$.

Work Step by Step

$(2x-2)(3x-4)$ 1. Multiply the first terms of each bracket together. $(2x)(3x) =6x^{2}$ 2. Multiply the outermost terms of each bracket together. $(2x)(-4) = -8x$ 3. Multiply the innermost terms of each bracket together. $(-2)(3x) = -6x$ 4. Multiply the last terms of each bracket together. $(-2)(-4) = 8$ 5. Add all answers from steps 1-4 to get $6x^{2} -8x-6x+8$. 6. Collect like terms to get $6x^{2} -14x+8$.
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