Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises - Page 21: 45

Answer

x=$-2y$

Work Step by Step

$x^{2}+4xy+4y^{2}$ =$x^{2}+2xy+2xy+4y^{2}$ =$x(x+2y)+2y(x+2y)$ $(x+2y)(x+2y)$$=0$ $(x+2y)^{2}$$=0$ x=$-2y$
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