## Finite Math and Applied Calculus (6th Edition)

$9x^{2}+6x+1$
$(3x+1)^{2}$ 1. Square the first term. $(3x)^{2} = 9x^{2}$ 2. Multiply the first term and second term inside the bracket together. Then multiply this answer by 2. So $(3x)(1)(2)=6x$ 3. Square the last term inside the bracket. $(1)^{2} =1$ 4. Add all your answers from steps 1-4 to get $9x^{2}+6x+1$.