Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.1 Polynomials - R.1 Exercises: 24

Answer

$(2a-4b)^{2}=4a^{2}-16ab+16b^{2}$

Work Step by Step

$(2a-4b)^{2}$ Rewrite this expression as $(2a-4b)(2a-4b)$ and evaluate the product: $(2a-4b)^{2}=(2a-4b)(2a-4b)=...$ $...=4a^{2}-8ab-8ab+16b^{2}=4a^{2}-16ab+16b^{2}$
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