Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.1 Polynomials - R.1 Exercises - Page R-5: 16

Answer

$(3p+2)(5p^{2}+p-4)=15p^{3}+13p^{2}-10p-8$

Work Step by Step

$(3p+2)(5p^{2}+p-4)$ Evaluate the product indicated by multiplying the first term and second term of the first factor by every element in the second factor separately: $(3p+2)(5p^{2}+p-4)=...$ $...=15p^{3}+3p^{2}-12p+10p^{2}+2p-8=...$ Simplify: $...=15p^{3}+13p^{2}-10p-8$
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