Answer
$(-4y^{2}-3y+8)-(2y^{2}-6y-2)=-6y^{2}+3y+10$
Work Step by Step
$(-4y^{2}-3y+8)-(2y^{2}-6y-2)$
To evaluate the subtraction, change the sign of every term inside the second parentheses and evaluate by combining like terms:
$-4y^{2}-3y+8-2y^{2}+6y+2=-6y^{2}+3y+10$
