Answer
$~~\int_{5}^{10}w'(t)~dt~~$ represents the number of pounds that the child grows from the end of the child's fifth year until the end of the child's tenth year.
Work Step by Step
We can state the Net Change Theorem as follows:
The integral of a rate of change is the net change:
$\int_{a}^{b}F'(x)~dx = F(b)- F(a)$
$~~w'(t)~~$ is the rate of growth of a child in pounds per year.
Therefore, $~~\int_{5}^{10}w'(t)~dt~~$ represents the number of pounds that the child grows from the end of the child's fifth year until the end of the child's tenth year.
