Answer
$\int (cos~x+\frac{1}{2}x)~dx = sin~x+\frac{1}{4}x^2+C$
Work Step by Step
We can find the general indefinite integral:
$\int (cos~x+\frac{1}{2}x)~dx = sin~x+\frac{1}{4}x^2+C$
Positive values of $C$ translate the graph vertically upward, while negative values of $C$ translate the graph vertically downward.