Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.2 - The Definite Integral - 5.2 Exercises - Page 390: 59

Answer

$0 \leq \int_{0}^{1} x^3~dx \leq 1$

Work Step by Step

On the interval $0 \leq x \leq 1$: $0 \leq x^3 \leq 1$ Therefore, by Property 8: $0(1-0) \leq \int_{0}^{1} x^3~dx \leq 1(1-0)$ $0 \leq \int_{0}^{1} x^3~dx \leq 1$
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