Answer
$2 \leq \int_{0}^{2} (x^3-3x+3)~dx \leq 10$
Work Step by Step
On the interval $0 \leq x \leq 2$:
$1 \leq x^3-3x+3 \leq 5$
Therefore, by Property 8:
$1(2-0) \leq \int_{0}^{2} (x^3-3x+3)~dx \leq 5(2-0)$
$2 \leq \int_{0}^{2} (x^3-3x+3)~dx \leq 10$
