Answer
1.4
Work Step by Step
$\int_{a}^{c}f(x)dx=\int_{a}^{b}f(x)dx+\int_{b}^{c}f(x)dx$
So $\int_{2}^{4}f(x)dx+\int_{4}^{8}f(x)dx=\int_{2}^{8}f(x)dx$
$5.9+\int_{4}^{8}f(x)dx=7.3$
$\int_{4}^{8}f(x)dx=1.4$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 5 - Section 5.2 - The Definite Integral - 5.2 Exercises - Page 390: 48
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