Answer
$$f'(x)=2xg'(x^2)$$
Work Step by Step
$f'(x)=\frac{d}{dx}g(x^2)$
Using the chain rule:
$f'(x)=\frac{dg(x^2)}{dx^2}\times\frac{dx^2}{dx}$
$=g'(x^2)\times 2x$
$=2xg'(x^2)$
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