Answer
$$f'(x)=2g(x)g'(x)$$
Work Step by Step
$f'(x)=\frac{d}{dx}[g(x)]^2$
Using the chain rule:
$f'(x)=\frac{d[g(x)]^2}{dg(x)}\times\frac{dg(x)}{dx}$
$=2g(x)\times g'(x)$
$=2g(x)g'(x)$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 3 - Review - Exercises - Page 268: 73
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