Answer
$$f'(x)=2xg(x)+x^2g'(x)$$
Work Step by Step
$f'(x)=\frac{dx^2g(x)}{dx}$
Using the product rule:
$f'(x)=2xg(x)+x^2g'(x)$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 3 - Review - Exercises - Page 268: 71
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