Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Review - Exercises: 71

Answer

$$f'(x)=2xg(x)+x^2g'(x)$$

Work Step by Step

$f'(x)=\frac{dx^2g(x)}{dx}$ Using the product rule: $f'(x)=2xg(x)+x^2g'(x)$
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