## Calculus: Early Transcendentals 8th Edition

$\lim\limits_{x\to0.5^-}\frac{2x-1}{|2x^3-x^2|}=-4$
$A=\lim\limits_{x\to0.5^-}\frac{2x-1}{|2x^3-x^2|}$ $A=\lim\limits_{x\to0.5^-}\frac{2x-1}{|x^2(2x-1)|}$ $A=\lim\limits_{x\to0.5^-}\frac{2x-1}{x^2|2x-1|}$ (for $x^2\geq0\hspace{0.5cm}\forall x\in R)$ Therefore, $A=\lim\limits_{x\to0.5^-}\frac{2x-1}{-x^2(2x-1)}$ $A=\lim\limits_{x\to0.5^-}\frac{1}{-x^2}$ $A=\frac{1}{-0.5^2}$ $A=-4$