# Chapter 11 - Section 11.2 - Series - 11.2 Exercises: 33

Diverges

#### Work Step by Step

$\lim _{n\rightarrow \infty }\dfrac {1}{4+e^{-n}}=\dfrac {1}{4+0}=\dfrac {1}{4}\neq 0\Rightarrow \sum ^{\infty }_{n=1}\dfrac {1}{4+e^{-n}}$. Diverges

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