Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.2 - Series - 11.2 Exercises: 53

Answer

$=2+\dfrac {516}{999}=\dfrac {2514}{999}$

Work Step by Step

$2.\overline {516}=2.516516\ldots =2+\dfrac {516}{1000}+\dfrac {516}{10000}+\ldots =2+\dfrac {a_{1}}{1-r};a_{1}=\dfrac {516}{1000};r=\dfrac {1}{1000}\Rightarrow 2.\overline {516}=2+\dfrac {\dfrac {516}{1000}}{1-\dfrac {1}{1000}}=2+\dfrac {516}{999}=\dfrac {2514}{999}$
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