## Calculus: Early Transcendentals (2nd Edition)

a) $\{10,5,2.5,1.25\}$ b) $h_n = 0.5^n(20)$
a) $h_0 = 20$; $h_n = r(h_{n-1})$ $h_n = 0.5h_{n-1}$ $h_1 = 0.5h_0 = 10$ $h_2 = 0.5h_1 = 5$ $h_3 = 0.5h_2 = 2.5$ $h_4 = 0.5h_3 = 1.25$ b) We need to multiply by a factor of $r$ a total of $n$ times to the original value of $h_0$. $h_n = r^nh_0 = 0.5^n(20)$