Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.1 An Overview - 8.1 Exercises - Page 605: 47

Answer

a) $\{\frac{5}{2},\frac{9}{4},\frac{17}{8},\frac{33}{16}\}$ b) $2$

Work Step by Step

$a_n = 2+2^{-n}$ Part a) $a_1 = 2+2^{-1} = \frac{5}{2}$ $a_2 = 2+2^{-2} = \frac{9}{4}$ $a_3 = 2+2^{-3} = \frac{17}{8}$ $a_4 = 2+2^{-4} = \frac{33}{16}$ Part b) The values of the sequence seem to slope off when $a_n=2$
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