## Calculus: Early Transcendentals (2nd Edition)

a) $\{\frac{4}{3},\frac{9}{8},\frac{16}{15},\frac{25}{24}\}$ b) $1$
$a_n = \frac{n^2}{n^2-1}$ Part a) $a_2 = \frac{2^2}{2^2-1} = \frac{4}{3}$ $a_3 = \frac{3^2}{3^2-1} = \frac{9}{8}$ $a_4 = \frac{4^2}{4^2-1} = \frac{16}{15}$ $a_5 = \frac{5^2}{5^2-1} = \frac{25}{24}$ Part b) The values of the sequence seems to slope off when $a_n = 1$